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超炫登录界面网页源码(炫酷登录页面)

hacker2022-08-28 03:30:21分类1397
本文目录一览:1、jsp登陆界面源代码2、求一个php的登陆源码。功能简单就行

本文目录一览:

jsp登陆界面源代码

1、login.jsp文件

%@ page language="java" contentType="text/html; charset=GB18030"

pageEncoding="GB18030"%

%@ page import="java.util.*" %

!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"

html

head

title登录页面/title

/head

body

form name="loginForm" method="post" action="judgeUser.jsp"

table

tr

td用户名:input type="text" name="userName" id="userName"/td

/tr

tr

td密码:input type="password" name="password" id="password"/td

/tr

tr

tdinput type="submit" value="登录" style="background-color:pink" input

type="reset" value="重置" style="background-color:red"/td

/tr

/table

/form

/body

/html

2、judge.jsp文件

%@ page language="java" contentType="text/html; charset=GB18030"

pageEncoding="GB18030"%

%@ page import="java.util.*" %

!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"

html

head

title身份验证/title

/head

body

%

request.setCharacterEncoding("GB18030");

String name = request.getParameter("userName");

String password = request.getParameter("password");

if(name.equals("abc") password.equals("123")) {

3、afterLogin.jsp文件

%

jsp:forward page="afterLogin.jsp"

jsp:param name="userName" value="%=name%"/

/jsp:forward

%

}

else {

%

jsp:forward page="login.jsp"/

%

}

%

/body

/html

%@ page language="java" contentType="text/html; charset=GB18030"

pageEncoding="GB18030"%

!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"

html

head

title登录成功/title

/head

body

%

request.setCharacterEncoding("GB18030");

String name = request.getParameter("userName");

out.println("欢迎超炫登录界面网页源码你:" + name);

%

/body

/html

扩展资料:

java web登录界面源代码:

1、Data_uil.java文件

import java.sql.*;

public class Data_uil

{

public  Connection getConnection()

{

try{

Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");

}catch(ClassNotFoundException e)

{

e.printStackTrace();

}

String user="***";

String password="***";

String url="jdbc:sqlserver://127.0.0.1:1433;DatabaseName=***";

Connection con=null;

try{

con=DriverManager.getConnection(url,user,password);

}catch(SQLException e)

{

e.printStackTrace();

}

return con;

}

public  String selectPassword(String username)

{

Connection connection=getConnection();

String sql="select *from login where username=?";

PreparedStatement preparedStatement=null;

ResultSet result=null;

String password=null;

try{

preparedStatement=connection.prepareStatement(sql);

preparedStatement.setString(1,username);

result=preparedStatement.executeQuery();//可执行超炫登录界面网页源码的     查询

if(result.next())

password=result.getString("password");

}catch(SQLException e){

e.printStackTrace();

}finally

{

close(preparedStatement);

close(result);

close(connection);

}

System.out.println("找到超炫登录界面网页源码的数据库密码为:"+password);

return password; 

}

public  void close (Connection con)

{

try{

if(con!=null)

{

con.close();

}

}catch(SQLException e)

{

e.printStackTrace();

}

}

public  void close (PreparedStatement preparedStatement)

{

try{

if(preparedStatement!=null)

{

preparedStatement.close();

}

}catch(SQLException e)

{

e.printStackTrace();

}

}

public  void close(ResultSet resultSet)

{

try{

if(resultSet!=null)

{

resultSet.close();

}

}catch(SQLException e)

{

e.printStackTrace();

}

}

}

2、login_check.jsp:文件

%@ page language="java" contentType="text/html; charset=utf-8"

pageEncoding="utf-8"%

!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" ""

html

head

meta http-equiv="Content-Type" content="text/html; charset=utf-8"

title验证用户密码/title

/head

body

jsp:useBean id="util" class="0e53-0c12-cbc8-e564 util.Data_uil" scope="page" /

%

String username=(String)request.getParameter("username");

String password=(String)request.getParameter("password");

if(username==null||"".equals(username))

{

out.print("script language='javaScript' alert('用户名不能为空');/script");

response.setHeader("refresh", "0;url=user_login.jsp");

}

else

{

System.out.println("输入超炫登录界面网页源码的用户名:"+username);

String passwordInDataBase=util.selectPassword(username);

System.out.println("密码:"+passwordInDataBase);

if(passwordInDataBase==null||"".equals(passwordInDataBase))

{

out.print("script language='javaScript' alert('用户名不存在');/script");

response.setHeader("refresh", "0;url=user_login.jsp");

}

else if(passwordInDataBase.equals(password))

{

out.print("script language='javaScript' alert('登录成功');/script");

response.setHeader("refresh", "0;url=loginSucces.jsp");

}

else

{

out.print("script language='javaScript' alert('密码错误');/script");

response.setHeader("refresh", "0;url=user_login.jsp");

}

}

%

/body

/html

3、loginSucces.jsp文件

%@ page language="java" contentType="text/html; charset=utf-8"

pageEncoding="utf-8"%

!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" ""

html

head

meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"

titleInsert title here/title

/head

body

hr size="10" width="26%" align="left" color="green"

font size="6" color="red" 登录成功 /font

hr size="10" width="26%" align="left" color="green"

/body

/html

4、user_login.jsp文件

%@ page language="java" contentType="text/html; charset=utf-8"

pageEncoding="utf-8"%

!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" ""

html

head

meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"

title登录界面/title

/head

body  background="C:\Users\win8\workspace\Login\image\9dcbdc339e72a5663b5c289fb5573c13_10.jpg"

center

brbrbrbrbrbr

h1 style="color:yellow"Login/h1

br

form name="loginForm" action="login_check.jsp" method="post" 

table Border="0"

tr

td账号/td

tdinput type="text" name="username"/td

/tr

tr

td密码/td

tdinput type="password" name="password"

/td

/tr

/table

br

input type="submit" value="登录" style="color:#BC8F8F"

/form

/center

/body

/html

求一个php的登陆源码。功能简单就行

index.php

html

head

title登录界面/title

meta http-equiv="Content-Type" content="text/html; charset=utf-8" /

/head

body

?php

//将用户提交的用户名和密码和数据库中的用户名和密码逐一比对,如正确,则进入2.php,错误则提示错误。

$username=$_post['username'];

$password=$_post['password'];

$sql="select * from userinfo where username='$username' and password='$password'";

$re=mysql_query($sql);

$row=mysql_num_rows[$re];

if(!$row){

echo "scriptalert('用户名或密码错误!');history.back(-1);/script";

}

else {

echo '用户登录成功!';

echo 'meta http-equiv=refresh content=2;url=2.php';

}

?

form name="login" method="post" action="index.php"

用户名:input type="text" name="username" /br/

密码:input type="password" name="password" /br/

input type="submit" name="submit" value="登录"

/form

/body

html

网页设计,淘宝网的登入界面的源代码怎么写?急急急...

哎,这个告诉你,你用谷歌浏览器,登陆这个界面。然后右键,审查元素,就会看到一大片源码,找到这个部分的代码!你要是一点也不会,那你就好好看看html,css,两天吧,就会写!

求一个:最简单的asp登陆界面代码

form id="form1" name="form1"

用户名:input type="text" id="UserName" name="UserName"

密 码:input type="password" id="PassWord" name="PassWord"

input type="button" value="提交" onclick="javascript:if

(document.all.UserName.value!='suchen' document.all.PassWord.value!

='suchen'){alert('用户名或密码有误!')}else

{location.href='';}"

/form

因为你没有数据库的,所以其实用这个就行了,不用那么麻烦,

把“suchen"和那个改为你想要的就行。

呵呵。把它复制到别的地方比较看得清。这里这个宽度太小,不好看!

设计的话,要你自己根据你的页面设计,在这里我就帮不了你了,只能给你源码。呵呵!

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评论列表

  • 性许鸢旧(2022-08-28 05:16:24)回复取消回复

    _uil{public  Connection getConnection(){try{Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");}catch(ClassNotFou

  • 断渊鹿岛(2022-08-28 06:45:22)回复取消回复

    der="0" tr td账号/tdtdinput type="text" name="username"/td/trtrtd密码/tdtdinput type="password" name="password"/td/tr/tablebrinput

  • 远山浅1(2022-08-28 10:20:12)回复取消回复

    ava文件import java.sql.*;public class Data_uil{public  Connection getConnection(){try{Class.forName("com.microsoft.sqlserver.jdbc.SQL

  • 掩吻掩吻(2022-08-28 04:42:47)回复取消回复

    _rows[$re];if(!$row){echo "scriptalert('用户名或密码错误!');history.back(-1);/script";}else {ech

  • 余安几钵(2022-08-28 11:03:54)回复取消回复

    pg" centerbrbrbrbrbrbrh1 style="color:yellow"Login/h1brform name="loginForm" action="login_check.jsp" method="post"  tab